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Question
The probability distribution function of a random variable X is given by
| xi : | 0 | 1 | 2 |
| pi : | 3c3 | 4c − 10c2 | 5c-1 |
where c > 0 Find: P (1 < X ≤ 2)
Sum
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Solution
P (1 < X ≤ 2)
\[= P\left( X = 2 \right)\]
\[ = 5c - 1\]
\[ = \frac{5}{3} - 1\]
\[ = \frac{5 - 3}{3}\]
\[ = \frac{2}{3}\]
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