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Question
The present population of the town is 2,00,000. The population is increased by 10% in the first year and 15% in the second year. Find the population of the town at the end of two years.
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Solution
Population after n years = Present population x `(1 + r/100)^n`
Present population = 2,00,000
After first year, population = = 2,00,000 xx `(1 + 10/100)^1`
`= 2,00,000 xx 11/10`
= 2,20,000
Population after two years = 2,20,000 `xx (1 + 15/100)^1`
= 253000
Thus, the population after two years is 2,53,000.
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