Question

The present age of a man is double the age of his son. After 8 years, the ratio of their ages will be 7 : 4. Find the present ages of the man and his son.

Answer 1

Let the son's age be x years, so the man's age is 2x years.
As per the given condition,

`(2x + 8)/(x + 8) = (7)/(4)`

⇒ 4(2x + 8) = 7(x + 8)
⇒ 8x + 32 = 7x + 56
⇒ 8x - 7x = 56 - 32
⇒ x = 24
Son's age = x years = 24 years
Man's age = 2x years = 2(24) = 48 years
Hence, son's age is 24 years and man's age is 48 years.