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The population of a town increases at a rate proportional to the population at that time. If the population increases from 40 thousands to 60 thousands in 40 years ? - Mathematics and Statistics

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Question

The population of a town increases at a rate proportional to the population at that time. If the population increases from 40 thousands to 60 thousands in 40 years, what will be the population in another 20 years?

(Given: `sqrt(3/2)= 1.2247)`

Sum
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Solution

Step 1: Use the Exponential Growth Model

P(t) = P0​ekt

where:

  • P = Population at time t
  • P0 = Initial population
  • k = Growth constant
  • t = Time in years

Step 2: Find k Using Given Data

We are given:

  • P0 = 40,000 
  • P(40) = 60,000
  • t = 40 years

60,000 = 40,000e40k

`(60,000)/(40,000) = e^(40k)`

1.5 = e40k

Taking the natural logarithm:

ln (1.5) = 40k

`k = ln(1.5)/40`

Using ln⁡ (1.5) = 0.4055

`k = 0.4055/40 = 0.01014`

Step 3: Find Population After 60 Years

Now, we need to find P(60)

P(60) = 40,000e60k

P(60) = 40,000e60×0.01014

P(60) = 40,000e0.6084

P(60) = 40,000 × 1.837

P(60) ≈ 73,480

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Chapter 8: Differential Equation and Applications - Exercise 8.6 [Page 170]

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Balbharati Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
Chapter 8 Differential Equation and Applications
Exercise 8.6 | Q 2 | Page 170
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