English

The population of a town increases at a rate proportional to the population at that time. If the population increases from 26,000 to 39,000 in 50 years, then the population in another 25 years will be

Advertisements
Advertisements

Question

The population of a town increases at a rate proportional to the population at that time. If the population increases from 26,000 to 39,000 in 50 years, then the population in another 25 years will be ______ `(sqrt(3/2) = 1.225)`

Options

  • 47757

  • 47775

  • 47575

  • 45777

MCQ
Fill in the Blanks
Advertisements

Solution

The population of a town increases at a rate proportional to the population at that time. If the population increases from 26,000 to 39,000 in 50 years, then the population in another 25 years will be `(sqrt(3/2) = 1.225)` 47775.

Explanation:

Let P be the population at time t years.

Then, `(dP)/dt = kP`

⇒ `(dP)/P = kdt`

Integrating on both sides, we get

log P = kt + c

When t = 0, P = 26000

∴ log 26000 = 0 + c ⇒ c = log 26000

∴ log P = kt + log 26000

⇒ `log(P/26000) = kt` .....................(i)

When t = 50 yrs, P = 39000

∴ `log(39000/26000) = 50 k ⇒ k = 1/50 log(3/2)`

∴ `log(P/26000) = t/50log(3/2)` .....[From(i)]

When t = 75 yrs, we have

`log(P/26000) = 75/50 log(3/2)`

⇒ `P/26000 = (3/2)^{3/2} ⇒ P/26000 = 3/2(3/2)^{1/2}`

⇒ P = `26000 xx 3/2 xx 1.225 = 47775`

shaalaa.com
Application of Differential Equations
  Is there an error in this question or solution?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×