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Question
The optical length of an astronomical telescope with magnifying power of ten for normal vision is 44 cm. what is the focal length of the object
Options
440 cm
49 cm
40 cm
4 cm
MCQ
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Solution
40 cm
Explanation:
m = `(fo)/(fe)` = 10
fo = 10 fe
L = fo + fe on 44 = 10fe + fe = 11fe
fe = 4 cm
fo = 10fe = 10 × 4 = 40 cm
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