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Question
The number of diagonals of an n-sided figure is `1/2(n^2 - 3n)`. Use the formula to find the number of diagonals for a 6-sided figure (hexagon).
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Solution
Given, a polygon has n sides, then number of diagonals is `1/2(n^2 - 3n)`.
In hexagon, there are six sides
Therefore for calculating number of diagonals in hexagon, put n = 6 in the above formula
∴ Number of diagonals = `1/2[n^2 - 3n]`
= `1/2(6^2 - 3 xx 6)`
= `1/2(6 xx 6 - 3 xx 6)`
= `1/2(36 - 18)`
= `1/2(18)`
= 9
Hence, a hexagon has 9 diagonals.
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RELATED QUESTIONS
Find the value of 93.
Express the following number in index form.
Sixth root of 9
Evaluate: 23 x 42
Evaluate: 33 x 52
Evaluate: `(- 3/4)^3 xx (2/3)^4`
Which is greater:
54 or 45
Complete the table below.
| Sr. No | Indices (Numbers in index form) |
Base | Index | Multiplication form | Value |
| (i) | 34 | 3 | 4 | 3 × 3 × 3 × 3 | 81 |
| (ii) | 163 | ||||
| (iii) | (−8) | 2 | |||
| (iv) | `3/7 xx 3/7 xx 3/7 xx 3/7` | `81/2401` | |||
| (v) | (−13)4 |
Fill in the blanks with <, > or = sign.
63 ______ 44
42 is greater than 24.
