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The moment of inertia of a body about a given axis is 1.2 kgm2. initially, the body is at rest. For what duration on the angular acceleration of 25 radian/sec2 must be applied about that axis - Physics

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Question

The moment of inertia of a body about a given axis is 1.2 kgm2. initially, the body is at rest. For what duration on the angular acceleration of 25 radian/sec2 must be applied about that axis in order to produce rotational kinetic energy of 1500 joule?  

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Solution

Given:

I = 1.2 kgm2, α = 25 radian/sec2, ω0 = 0 rad/s, (K.E.)rot = 1500 J 

To find: Time (t)

Formulae:

i. α = `(ω - ω_0)/t`

ii. K.E. = `1/2"Iω"^2`

Calculation: 

From formula (i),

25 = `(ω - 0)/t`

∴ ω = 25t

From formula (ii),

1500 = `1/2 xx 1.2 xx (25t)^2`

∴ t = `sqrt((2 xx 1500)/(1.2 xx 25^2)) = sqrt4`

∴ t = 2 sec.

An angular acceleration must be applied for 2 sec.  

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Chapter 1: Rotational Dynamics - Short Answer I

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