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Question
The minimum value of the expression 3x + 31–x, x ∈ R, is ______.
Options
0
`1/3`
3
`2sqrt(3)`
MCQ
Fill in the Blanks
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Solution
The minimum value of the expression 3x + 31–x, x ∈ R, is `2sqrt(3)`.
Explanation:
We know A.M. ≥ G.M. for positive numbers.
Therefore, `(3^x 6 3(1 - x))/2 ≥ sqrt(3^x * 3^(1 - x))`
⇒ `(3^x + 3^(l - x))/2 ≥ sqrt(3^x * 3/3^x)`
⇒ `3^x + 3^(1 - x) ≥ 2sqrt(3)`
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