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Question
The median of the following data is 32.5, find the missing frequencies x and y:
| Class: | 0 – 10 | 10 – 20 | 20 – 30 | 30 – 40 | 40 –50 | 50 – 60 | 60 – 70 | Total |
| Frequency: | x | 5 | 9 | 12 | y | 3 | 2 | 40 |
Sum
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Solution
Total frequency Σf = 40.
x + 5 + 9 + 12 + y + 3 + 2 = 40
⇒ x + y + 31 = 40
⇒ x + y = 9 ...(Equation 1)
Median is 32.5, which falls in class 30 – 40.
Median Formula: `M = l + ((N//2 - cf)/f) xx h`.
Here, l = 30, N/2 = 20, f = 12, h = 10.
Cumulative frequency before median class (cf) = x + 5 + 9 = x + 14.
`32.5 = 30 + ((20 - (x + 14))/12) xx 10`
`2.5 = ((6 - x)/12) xx 10`
`2.5 xx 12/10 = 6 - x`
⇒ 3 = 6 – x
⇒ x = 3
Substitute x = 3 into equation (1):
3 + y = 9
⇒ y = 6
The missing frequencies are x = 3 and y = 6.
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