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Question
The mean of 5 observations is 4.8 and their variance is 4.56. If three observations are 2, 3, and 5, the other two observations are ______
Options
4 and 8
6 and 8
5 and 7
5 and 9
MCQ
Fill in the Blanks
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Solution
The mean of 5 observations is 4.8 and their variance is 4.56. If three observations are 2, 3, and 5, the other two observations are 6 and 8.
Explanation:
Let the two unknown items be x and y, then x = 4.8
⇒ `(2 + 3 + 5 + x + y)/5 = 4.8`
⇒ x + y = 14
Here, variance = 4.56
∴ `(2^2 + 3^2 + 5^2 + x^2 + y^2)/5 - ("mean")^2 = 4.56`
x2 + y2 = 100
Solving, x = 6, y = 8 or x = 8, y = 6
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Range, Variance and Standard Deviation
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