Question

The mean of a binomial distribution is 10 and its standard deviation is 2; write the value of q.

 

Answer 1

\[\text{ Mean of the binomial distribution, i . e . np } = 10\]
\[\text{ Variance } = \left( \text{ Standard deviation } \right)^2 ,\text{  i . e . npq }  = 4\]
\[ \therefore q = \frac{\text{ Variance } }{\text{ Mean} } = 0 . 4 \]