Advertisements
Advertisements
Question
The mass of a lead piece is 115 g. When it is immersed into a measuring cylinder, the water level rises from 20 ml mark to 30 ml mark.
Find the volume of the lead piece.
Advertisements
Solution
Given: M = 115 g
V1 = 20 ml
V2 = 30 ml
Volume of lead piece V = V2 − V1
= 30 ml − 20 ml
= 10 ml or 10 cm3 [∴ 1 ml = 1 cm3]
APPEARS IN
RELATED QUESTIONS
Define the term volume of an object.
How will you determine the volume of a cuboid ? Write the formula you will use.
Name two devices which are used to measure the volume of an object. Draw their neat diagrams.
‘The density of brass is 8.4 g cm’3’. What do you mean by the statement ?
The mass of an iron ball is 312 g. The density of iron is 7.8 g cm-3. Find the volume of the ball.
A cork has a volume 25 cm3. The density of cork is 0.25 g cm-3. Find the mass of cork.
The mass of a lead piece is 115 g. When it is immersed into a measuring cylinder, the water level rises from 20 ml mark to 30 ml mark ,
Find the density of the lead in kg m-3.
State true or false. If false, correct the statement.
The region covered by the boundary of a plane figure is called its volume.
What are the other units used to measure the volume of liquids?
Questions based on Higher Order Thinking Skills:
|
There are three spheres A, B, C as shown below. Sphere A and B are made of the same material. Sphere C is made of a different material. Spheres A and C have equal radii. The radius of sphere B is half that of A. Density of A is double that of C.
|
Now answer the following questions.
- Find the ratio of masses of spheres A and B.
- Find the ratio of volumes of spheres A and B.
- Find the ratio of masses of spheres A and C.
