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Question
The length of the latus rectum of the hyperbola \[3x^{2}-y^{2}=4\] is______.
Options
\[8\sqrt{3}\]
\[4\sqrt{3}\]
16
32
MCQ
Fill in the Blanks
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Solution
The length of the latus rectum of the hyperbola \[3x^{2}-y^{2}=4\] is \[4\sqrt{3}\].
Explanation:
Rewrite in standard form:
\[3x^2-y^2=4\Rightarrow\frac{x^2}{\frac{4}{3}}-\frac{y^2}{4}=1\]
So \[a^2=\frac{4}{3},b^2=4.\]
Length of latus rectum of hyperbola \[=\frac{2b^2}{a}{:}\]
\[a=\sqrt{\frac{4}{3}}=\frac{2}{\sqrt3}\]
Latus rectum = \[\frac{2\times4}{\frac{2}{\sqrt{3}}}=\frac{8}{\frac{2}{\sqrt{3}}}=8\times\frac{\sqrt{3}}{2}=4\sqrt{3}\]
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