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Question
The length of a chord is 30 cm and it is at a distance of 8 cm from the centre of the circle. Find the radius.
Sum
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Solution
Given:
- The length of the chord is 30 cm, so half the length of the chord is:
`30/2 = 15` cm - The distance from the center of the circle to the chord is 8 cm.
Let r be the radius of the circle.
In this case, we have a right-angled triangle formed by:
- The radius of the circle (hypotenuse) = r,
- The distance from the center of the circle to the chord (one leg) = 8 cm,
- Half the length of the chord (the other leg) = 15 cm.
Using the Pythagorean theorem:
r2 = (distance from center to chord)2 + (half of the chord length)2
Substitute the values:
r2 = 82 + 152
r2 = 64 + 225
r2 = 289
`r = sqrt(289) = 17` cm
Thus, the radius of the circle is 17 cm.
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