Advertisements
Advertisements
Question
The joint equation of bisectors of angles between lines x = 5 and y = 3 is ______
Options
(x - 5) (y - 3) = 0
x2 - y2 - 10x + 6y + 16 = 0
xy = 0
xy - 5x - 3y + 15 = 0
MCQ
Fill in the Blanks
Advertisements
Solution
The joint equation of bisectors of angles between lines x = 5 and y = 3 is x2 - y2 - 10x + 6y + 16 = 0.
Explanation:

The equations of bisectors are,
y - 3 = (1)(x - 5) and y - 3 = (-1)(x - 5)
⇒ x - y - 2 = 0 and x + y - 8 = 0
∴ The joint equation of the bisectors is
(x - y - 2)(x + y - 8) = 0
⇒ x2 - y2 - 10x + 6y + 16 = 0
shaalaa.com
Formation of Joint Equation and Separation of Equations from a Given Equation
Is there an error in this question or solution?
