Question

The integrating factor (I.F.) of `dy/dx + y = e^-x` is e^x.

Answer 1

This statement is true.

Explanation:

For a first-order linear differential equation in the form `dy/dx + P(x)y = Q(x)`, the integrating factor is calculated as `e^(int P(x)dx)`.

In your equation, P(x) = 1, so the calculation is:

I.F. = `e^(int 1dx)`

= e^x