Question

The horizontal component of the earth's magnetic field at a place is `1/sqrt(3)` time the vertical component. Determine the angle of dip at that place.

Answer 1

Let angle of dip = θ, vertical component = V Tesla
∴                                          tan θ = `V/H = V/(1/sqrt(3)V)= sqrt(3) `=  tan 60°

                                                              θ = 60°