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The Height of a Right Circular Cylinder is 10.5 M. Three Times the Sum of the Areas of Its Two Circular Faces is Twice the Area of the Curved Surface. Find the Volume of the Cylinder. - Mathematics

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Question

The height of a right circular cylinder is 10.5 m. Three times the sum of the areas of its two circular faces is twice the area of the curved surface. Find the volume of the cylinder.

Sum
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Solution

It is known that three times the sum of the areas of the two circular faces, of the right circular cylinder, is twice the area of the curved surface.
Hence, it can be written using the following formula:
3 (2πr2) = 2(2πrh)
3πr2 = 2πrh
3r = 2h
It is known that the height of the cylinder (h) is 10.5 m.
Substituting this number in the equation:
3r = 2(10.5)
r = 7 m

Volume of the cylinder = πr2h
                             = 22 (72) (10.5)
                                7
                             = 1617 m3
Thus, the volume of the cylinder is 1617 m3.

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Chapter 22: Mensuration - III (Surface Area and Volume of a Right Circular Cylinder) - Exercise 22.2 [Page 25]

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RD Sharma Mathematics [English] Class 8
Chapter 22 Mensuration - III (Surface Area and Volume of a Right Circular Cylinder)
Exercise 22.2 | Q 18 | Page 25
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