Question

The following reaction is feasible or not feasible and why?

\[\ce{Br2 + 2NaI -> 2NaBr + I2}\]

Answer 1

1. This is a halogen displacement reaction where bromine (Br₂) reacts with sodium iodide (NaI).
2. Bromine is more reactive than iodine, so it can displace iodine from sodium iodide.
3. The reaction forms sodium bromide (NaBr) and iodine (I₂).
4. To check feasibility, EMF values of half reactions (Br₂/Br⁻) and (I₂/I⁻) are compared.
5. Bromine has a higher standard electrode potential (+1.09 V) than iodine (+0.54 V).
6. The EMF of the cell is positive, implying the reaction is spontaneous and feasible.

Therefore, the reaction proceeds as bromine displaces iodine from sodium iodide.