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Question
The following frequency distribution table shows the distances travelled by some rickshaws in a day. Observe the table and answer the following questions
| Class (Daily distance travelled in km) |
Continuous Classes |
Frequency (no.of. rickshaws) |
Cumulative frequency less than type |
| 60 – 64 | 59.5 – 64.5 | 10 | 10 |
| 65 – 69 | 64.5 – 69.5 | 34 | 10 + 34 = 44 |
| 70 – 74 | 69.5 – 74.5 | 58 | 44 + 58 = 102 |
| 75 – 79 | 74.5 – 79.5 | 82 | 102 + 82 = 184 |
| 80 – 84 | 79.5 – 84.5 | 10 | 184 + 10 = 194 |
| 85 – 89 | 84.5 – 89.5 | 6 | 194 + 6 = 200 |
- Which is the modal class? Why?
- Which is the median class and why?
- Write the cumulative frequency (C.F) of the class preceding the median class.
- What is the class interval (h) to calculate median?
Sum
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Solution
1. Model class is the class that contains highest frequency i.e.
highest frequency = 82
highest frequency class = 75 – 79
2. Median class is the class that contain `(N/2)^(th)` term. Where N is total frequency.
N = 200
`(N/2) = 100`
`(N/2)^(th)` term will lie in (70 – 74) class
3. Cumulative frequency = 44
4. Median class = 70 – 74
OR
69.5 – 74.5 ......(Continuous)
h = U.l. – L.l.
= 74.5 – 69.5 = 5
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