Question

The following distribution gives the number of accidents met by 160 workers in a factory during a month.

No. of accidents(x)	0	1	2	3	4
No. of workers (f)	70	52	34	3	1

Find the average number of accidents per worker.

Answer 1

Let the assumed mean (A) = 2

No. of Accidents (x1)	No. of workers (f1)	u1 = x1 - A = x1 - 2	f1u1
0	70	-2	-140
1	52	-1	-52
2	34	0	0
3	3	1	3
4	1	2	2
	N = 160		`sumf_1"u"_1=-187`

Average no of accidents per day workers `=A+(sumf_1"u"_1)/N`

`=2+(-187)/160`

`=2-187/160`

`=(320-187)/160`

`=133/160`

= 0.83