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Question
The following are the marks (out of 100) of 60 students in mathematics.
16, 13, 5, 80, 86, 7, 51, 48, 24, 56, 70, 19, 61, 17, 16, 36, 34, 42, 34, 35, 72, 55, 75, 31, 52, 28, 72, 97, 74, 45, 62, 68, 86, 35, 85, 36, 81, 75, 55, 26, 95, 31, 7, 78, 92, 62, 52, 56, 15, 63, 25, 36, 54, 44, 47, 27, 72, 17, 4, 30.
Construct a grouped frequency distribution table with width 10 of each class, in such a way that one of the classes is 10 – 20 (20 not included).
Sum
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Solution
We arrange the given data into groups like 0 – 10, 10 – 20, 20 – 30 in which upper-class limit is not included in that class. The class width in each case is 10.
The frequency distribution of the given data is given below:
| Class interval | Tally marks | Frequency |
| 0 – 10 | `bb|bb|bb|bb|` | 4 |
| 10 – 20 | `\cancel(bb|bb|bb|bb|) bb|bb|` | 7 |
| 20 – 30 | `\cancel(bb|bb|bb|bb|)` | 5 |
| 30 – 40 | `bb|bb|bb|bb| bb|bb|bb|bb|` | 10 |
| 40 – 50 | `bb|bb|bb|bb|` | 5 |
| 50 – 60 | `bb|bb|bb|bb| bb|bb|bb|` | 8 |
| 60 – 70 | `bb|bb|bb|bb|` | 5 |
| 70 – 80 | `bb|bb|bb|bb| bb|bb|bb|` | 8 |
| 80 – 90 | `bb|bb|bb|bb|` | 5 |
| 90 – 100 | `bb|bb|bb|` | 3 |
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