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The focal length of a this lens in vacuum is f. If the material of the lens has µ = 3/2, its focal length when immersed in water refractive index 4/3 will -

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Question

The focal length of a this lens in vacuum is f. If the material of the lens has µ = 3/2, its focal length when immersed in water refractive index 4/3 will

Options

  • F

  • 4f/3

  • 3f

  • 4f

MCQ

Solution

4f

Explanation:

`1/(Fa) = ((ug)/(ua) - 1) (1/R_1 - 1/R_2)`

`1/(Fw) = ((ug)/(muw) - 1) (1/R_1 - 1/R_2)`

∴ Dividing (i) by (ii) we get

`(fw)/(fa) = (((mug)/(mua - 1)))/(((mug)/(muw - 1))`

= `((3/(2 - 1)))/(((3/2)/(4/2) = 1)`

= `(1/2)/(1/0)` = 4

fw = 4fa = 4f

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Diffraction of Light - The Single Slit
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