English

The equation tan–1x – cot–1x = (13) has ______. - Mathematics

Advertisements
Advertisements

Question

The equation tan–1x – cot–1x = `(1/sqrt(3))` has ______.

Options

  • No solution

  • Unique solution

  • Infinite number of solutions

  • Two solutions

MCQ
Fill in the Blanks
Advertisements

Solution

The equation tan–1x – cot–1x = `(1/sqrt(3))` has unique solution.

Explanation:

We have tan–1x – cot–1x = `pi/6` and tan–1x + cot–1x = `pi/2`

Adding them, we get 2tan–1x = `(2pi)/3`

⇒ tan–1x = `pi/3`

i.e., x = `sqrt(3)`.

shaalaa.com
  Is there an error in this question or solution?
Chapter 2: Inverse Trigonometric Functions - Solved Examples [Page 34]

APPEARS IN

NCERT Exemplar Mathematics [English] Class 12
Chapter 2 Inverse Trigonometric Functions
Solved Examples | Q 39 | Page 34

RELATED QUESTIONS

Find the principal value of the following:

`cos^(-1) (-1/2)`


Find the principal value of the following:

`cos^(-1) (-1/sqrt2)`


In ΔABC, if a = 18, b = 24, c = 30 then find the values of sinA.


Find the principal value of the following: sin-1 `(1/sqrt(2))`


Evaluate the following:

`tan^-1 sqrt(3) - sec^-1 (-2)`


Prove the following:

`cos^-1(3/5) + cos^-1(4/5) = pi/(2)`


Prove the following: 

`2tan^-1(1/3) = tan^-1(3/4)`


The principal value of cos−1`(-1/2)` is ______


Prove that `2 tan^-1 (3/4) = tan^-1(24/7)`


Prove that cot−1(7) + 2 cot−1(3) = `pi/4`


Show that `sin^-1(3/5)  + sin^-1(8/17) = cos^-1(36/85)`


Prove that `2 tan^-1 (1/8) + tan^-1 (1/7) + 2tan^-1 (1/5) = pi/4`


Find the principal value of the following:

cosec-1 (2)


Solve: tan-1 (x + 1) + tan-1 (x – 1) = `tan^-1 (4/7)`


Show that `sin^-1 (- 3/5) - sin^-1 (- 8/17) = cos^-1 (84/85)`


The value of cot `(tan^-1 2x + cot^-1 2x)` is ______ 


In ΔABC, tan`A/2 = 5/6` and tan`C/2 = 2/5`, then ______


The principle solutions of equation tan θ = -1 are ______ 


If `sin^-1x + cos^-1y = (3pi)/10,` then `cos^-1x + sin^-1y =` ______ 


`cos(2sin^-1  3/4+cos^-1  3/4)=` ______.


If `3sin^-1((2x)/(1 + x^2)) - 4cos^-1((1 - x^2)/(1 + x^2)) + 2tan^-1((2x)/(1 - x^2)) = pi/3`, then x is equal to ______ 


The value of `sin^-1[cos(pi/3)] + sin^-1[tan((5pi)/4)]` is ______.


The domain of y = cos–1(x2 – 4) is ______.


The domain of the function defined by f(x) = sin–1x + cosx is ______.


Show that `2tan^-1 (-3) = (-pi)/2 + tan^-1 ((-4)/3)`


Prove that `tan^-1  1/4 + tan^-1  2/9 = sin^-1  1/sqrt(5)`


If `"sin"^-1("x"^2 - 7"x" + 12) = "n"pi, AA "n" in "I"`, then x = ____________.


If sin-1 x – cos-1 x `= pi/6,` then x = ____________.


If tan-1 (x – 1) + tan-1 x + tan-1 (x + 1) = tan-1 3x, then the values of x are ____________.


If 6sin-1 (x2 – 6x + 8.5) = `pi`, then x is equal to ____________.


`"tan"^-1 sqrt3 - "sec"^-1 (-2)` is equal to ____________.


sin 6θ + sin 4θ + sin 2θ = 0, then θ =


If `(-1)/sqrt(2) ≤ x ≤ 1/sqrt(2)` then `sin^-1 (2xsqrt(1 - x^2))` is equal to


Domain and Rariges of cos–1 is:-


What is the values of `cos^-1 (cos  (7pi)/6)`


If f(x) = x5 + 2x – 3, then (f–1)1 (–3) = ______.


If ax + b (sec (tan–1 x)) = c and ay + b (sec.(tan–1 y)) = c, then `(x + y)/(1 - xy)` = ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×