English

The equation of the plane through (-1, 1, 2), whose normal makes equal acute angles with co-ordinate axes is ______

Advertisements
Advertisements

Question

The equation of the plane through (-1, 1, 2), whose normal makes equal acute angles with co-ordinate axes is ______ 

Options

  • `overliner.(hati + hatj + hatk) = 2`

  • `overliner.(hati + hatj + hatk) = 6`

  • `overliner.(3hati - 3hatj + 3hatk) = 2`

  • `overliner.(hati - hatj + hatk) = 3`

MCQ
Fill in the Blanks
Advertisements

Solution

The equation of the plane through (-1, 1, 2), whose normal makes equal acute angles with co-ordinate axes is `underline(overliner.(hati + hatj + hatk) = 2)`

Explanation:

Let A ≡ (-1, 1, 2)

∴ `overlinea = -hati + hatj + 2hatk`

`overlinen = hati + hatj + hatk`

∴ equation of plane is `overliner.overlinen = overlinea.overlinen`

⇒ `overliner.(hati + hatj + hatk) = (-hati + hatj + 2hatk).(hati + hatj + hatk)`

⇒ `overliner.(hati + hatj + hatk) = 2`

shaalaa.com
Acute Angle Between a Pair of Straight Lines
  Is there an error in this question or solution?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×