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Question
The equation of the normal to the curve 2x2 + y2 = 12 at the point (2, 2) is ______.
Options
2x + y - 6 = 0
x - 2y + 2 = 0
2x - y + 6 = 0
x + 2y + 2 = 0
MCQ
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Solution
The equation of the normal to the curve 2x2 + y2 = 12 at the point (2, 2) is x - 2y + 2 = 0.
Explanation:
Given curve, 2x2 + y2 = 12
`=> 4x + 2y "dy"/"dx" = 0`
`"dy"/"dx" = (- 2x)/y`
Slope of tangent at (2, 2) is
`("dy"/"dx")_(2,2) = (- 2(2))/2` = - 2
∴ Slope of Normal = `- "dx"/"dy" = 1/2`
Equation of normal at (2, 2) is
`y - 2 = 1/2 (x - 2)`
⇒ 2y - 4 = x - 2
⇒ x - 2y + 2 = 0
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Application of Derivative in Geometry
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