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Question
The energy of an electron having de-Broglie wavelength `λ` is ______.
(h = Plank's constant, m = mass of electron)
Options
`"h"/(2"m"lambda)`
`"h"^2/(2"m"lambda^2)`
`"h"^2/(2"m"^2lambda^2)`
`"h"^2/(2"m"^2lambda)`
MCQ
Fill in the Blanks
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Solution
The energy of an electron having de-Broglie wavelength `λ` is `underlinebb("h"^2/(2"m"lambda^2))`.
(h = Plank's constant, m = mass of electron)
Explanation:
de-Broglie wavelength
λ = `"h"/"p" "h"/sqrt(2"m K.E")`
or, λ2 = `"h"^2/(2"m"("K"."E"))`
∴ K. E. = `"h"^2/(2"m"lambda^2)`
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De Broglie Hypothesis
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