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Question
The diagram represents the floor of a room. All dimensions are in metres and all the angles are right angles. Calculate

- the perimeter of the room
- the area of the floor
- the volume of the room if it is 3 m high.
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Solution
We have,
The diagram represents the floor of a room. All dimensions are in metres and all the angles are right angles. Calculate the perimeter of the room

Now we know that,
i. The perimeter of a polygon is the sum of all its sides
Then, the perimeter of the room is AB + BC + CD + DE + EF + FG + GH + HA
Therefore, the perimeter of the room is 2 + 2 + 3 + 2 + 2 + 6 + 7 + 6 = 30 m
ii. Then area of rectangle AHGF = 6 × 7 = 42 m2
And the area of rectangle BCDE = 3 × 2 = 6 m2
Then, the area of the floor = Area of rectangle AHGF – Area of rectangle BCDE
Therefore, the area of the floor = 42 – 6 = 36 m2
iii. The area of a rectangle is (Length)(Breadth)
Then area of rectangle AHGF = 6 × 7 = 42 m3
And the area of rectangle BCDE = 3 × 2 = 6 m3
Then, the area of the floor = Area of rectangle AHGF – Area of rectangle BCDE
The area of the floor = 42 – 6 = 36 m3
Now the volume of the room = (Area of the floor) × (Height)
Therefore, the volume of the room is 36 × 3 = 108 m3
