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Question
The de Broglie wavelength of an electron in the 4th Bohr orbit is ______.
Options
2πa0
4πa0
6πa0
8πa0
MCQ
Fill in the Blanks
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Solution
The de Broglie wavelength of an electron in the 4th Bohr orbit is 8πa0.
Explanation:
2πr = nλ
r = `("n"^2"a"_0)/"Z"`
`2π xx 4^2/1"a"_0` = 4λ
⇒ λ = `2π xx 4/1"a"_0`
⇒ λ = 8πa0
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