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Question
The current in 1 Ω resistor in the following circuit is ______.

Options
1 A
0.5 A
1.1 A
0.8 A
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Solution
The current in 1 Ω resistor in the following circuit is 1 A.
Explanation:
Condition for balanced Wheatstone-bridge,
`"P"/"Q" = "R"/"S"`
`=> 5/1 = 50/10`
`=> 5/1 = 5/1`
So, it is a balanced wheatstone-bridge and hence no current will flow through the arm G.
The circuit can be redrawn as given below,

As, we know that in a series branch, same current flows.
Hence, from the KVL loop rule,
VPQ = l1(5 + 1) = 6l1 ...(i)
and VRS = (50 + 10)(1.1 - l1) ...(ii)
Since, for the parallel branches, the voltage drop across them remains same,
So, VPQ = VRS
`=> 6l_1 = 60(1.1 - l_1)` ...(using Eqs. (i) and (ii))
⇒ l1(60 + 6) = 66
⇒ l1 = 1 A
Hence, current of 1 A passes through 1 Ω resistance.
