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Question
The correct order of the stoichiometries of AgCl formed when AgNO3 in excess is treated with the complexes:
CoCl3·6NH3, CoCl3·5NH3, CoCl3·4NH3 respectively is:
Options
1 AgCl, 3AgCl, 2AgCl
3 AgCl, 1 AgCl, 2 AgCl
3 AgCl, 2 AgCl, 1 AgCl
2 AgCl, 3 AgCl, 1 AgCl
MCQ
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Solution
3 AgCl, 2 AgCl, 1 AgCl
Explanation:
The number of AgCl precipitates depends on the number of free Cl− ions (outside the coordination sphere):
- CoCl3·6NH3 → [Co(NH3)6]Cl3 → 3 free Cl− → 3 AgCl
- CoCl3·5NH3 → [Co(NH3)5Cl]Cl2 → 2 free Cl− → 2 AgCl
- CoCl3·4NH3 → [Co(NH3)4Cl2]Cl → 1 free Cl− → 1 AgCl
The correct order is: 3 AgCl, 2 AgCl, 1 AgCl
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