Question

The conductivity of 0.2 M KCl solution is 3 × 10⁻² ohm⁻¹ cm⁻¹. Calculate its molar conductance.

Answer 1

Given:

Specific conductivity (κ) = 3 × 10⁻² Ω⁻¹ cm⁻¹

Concentration (C) = 0.2 mol/L

To find:

Molar conductance (Λ_m) = ?

Formula:

`Lambda_m = (kappa xx 1000)/C`

= `(3 xx 10^-2 xx 1000)/0.2`

= `30/0.2`

= 150 S cm² mol⁻¹