Question

The charge required for the reduction of 1 mol of \[\ce{MnO^-_4}\] to MnO₂ is ______.

Options

• 1 F

• 3 F

• 5 F

• 6 F

Answer 1

The charge required for the reduction of 1 mol of \[\ce{MnO^-_4}\] to MnO₂ is 3 F.

Explanation:

The oxidation state of Mn in MnO4 is +7. Mn has an oxidation state of +4 in MnO2. This means that the oxygen state has changed by 3. Thus, a charge of 3 F is required.