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Question
The average score of girls in class X examination in school is 67 and that of boys is 63. The average score for the whole class is 64.5. Find the percentage of girls and boys in the class.
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Solution
Let the number of girls and boys be n1 and n2 respectively.
We have
`bar"X"_1` = Average score of girls = 67
`bar"X"_2` = Average score of boys = 63
`bar"X"` = Average score of the whole class = 64·5
∴ `bar"X" = ("n"_1bar"X"_1 + "n"_2bar"X"_2)/("n"_1 + "n"_2)`
⇒ 64·5 = `(67"n"_1 + 63"n"_2)/("n"_1 + "n"_2)`
⇒ 64·5n1 + 64·5n2 = 67n1 + 63n2
⇒ 2·5n1 = 1·5n2
⇒ 25n1 = 15n2
⇒ 5n1 = 3n2
Total number of students in the class = n1 + n2.
∴ Percentage of girls = `("n"_1)/("n"_1 + "n"_2) xx 100`
= `("n"_1)/("n"_1 + (5"n"_1)/(3)) xx 100`, ...[∵ 5n1 = 3n2]
= `(3"n"_1)/(3"n"_1 + 5"n"_1) xx 100`
= `(3)/(8) xx 100`
= 37·5%
and
Percentage of boys = `("n"_2)/("n"_1 + "n"_2) xx 100`
= `("n"_2)/((3"n"_2)/(5) + "n"_2) xx 100`
= `(5"n"_2)/(3"n"_2 + 5"n"_2) xx 100`
= 62·5%
Hence, there are 37·5% girls and 62·5% boys in the class.
