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# The Atomic Mass of Uranium ""_92^238"U is 238.0508 U, While that of Thorium""_90^234"Th"Is 234.0436u, and that of Helium ""_2^4"He" - Physics (Theory)

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Numerical

The atomic mass of Uranium ""_92^238"U" is 238.0508 u, while that of Thorium ""_90^234"Th" is 234.0436u, and that of Helium ""_2^4"He" "is 4.0026u. Alpha decay converts ""_92^238"U" into ""_92^234"Th" as, shown below:

""_92^238"U" -> ( ""_90^234"Th" + ""_2^4"He" + "Energy" )

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#### Solution

The given nuclear reaction is
""_92^238"U" -> ""_90^234"Th" + ""_2^4"He" + "Energy"

To find the energy released in the above reaction, we have to find the mass object Δm.

Total mass of the reactants = 238.0508 u

Total mass of the products = 234.0436 + 4.0026
Total mass of the products = 238.0462 u

∴ Δm = 238.0508 - 238.0462
∴ Δm = 0.0046 u
∴ Energy released = 0.0046 x 931.0 MeV
Energy released = 4.28 MeV

Concept: Atomic Masses and Composition of Nucleus
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