Advertisements
Advertisements
प्रश्न
The atomic mass of Uranium `""_92^238"U"` is 238.0508 u, while that of Thorium `""_90^234"Th"` is 234.0436u, and that of Helium `""_2^4"He"` "is 4.0026u. Alpha decay converts `""_92^238"U"` into `""_92^234"Th"` as, shown below:
`""_92^238"U" -> ( ""_90^234"Th" + ""_2^4"He" + "Energy" )`
Advertisements
उत्तर
The given nuclear reaction is
`""_92^238"U" -> ""_90^234"Th" + ""_2^4"He" + "Energy"`
To find the energy released in the above reaction, we have to find the mass object Δm.
Total mass of the reactants = 238.0508 u
Total mass of the products = 234.0436 + 4.0026
Total mass of the products = 238.0462 u
∴ Δm = 238.0508 - 238.0462
∴ Δm = 0.0046 u
∴ Energy released = 0.0046 x 931.0 MeV
Energy released = 4.28 MeV
APPEARS IN
संबंधित प्रश्न
In the study of Geiger-Marsdon experiment on scattering of α particles by a thin foil of gold, draw the trajectory of α-particles in the coulomb field of target nucleus. Explain briefly how one gets the information on the size of the nucleus from this study.
From the relation R = R0 A1/3, where R0 is constant and A is the mass number of the nucleus, show that nuclear matter density is independent of A
A nucleus of mass number A has a radius R such that ______.
Deuteron is a bound state of a neutron and a proton with a binding energy B = 2.2 MeV. A γ-ray of energy E is aimed at a deuteron nucleus to try to break it into a (neutron + proton) such that the n and p move in the direction of the incident γ-ray. If E = B, show that this cannot happen. Hence calculate how much bigger than B must E be for such a process to happen.
Before the neutrino hypothesis, the beta decay process was throught to be the transition, `n -> p + vece`. If this was true, show that if the neutron was at rest, the proton and electron would emerge with fixed energies and calculate them. Experimentally, the electron energy was found to have a large range.
James Chadwick, in 1932 studied the emission of neutral radiations when Beryllium nuclei were bombarded with alpha particles. He concluded that emitted radiations were neutrons and not photons. Explain.
Two nuclei may have the same radius, even though they contain different numbers of protons and neutrons. Explain.
Which of the following are the constituents of the nucleus?
A nucleus with mass number 240 breaks into two fragments each of mass number 120, the binding energy per nucleon of unfragmented nuclei is 7.6 MeV while that of fragments is 8.5 MeV. The total gain in the binding energy in the process is:
The volume occupied by an atom is greater than the volume of the nucleus by a factor of about:
Energy equivalent of 1 amu is:
