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Question
The areas of two concentric circles are 1386 cm2 and 962.5 cm2. The width of the ring is
Options
2.8 cm
3.5 cm
4.2 cm
3.8 cm
MCQ
Sum
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Solution
3.5 cm
Let r cm and R cm be the radii of two concentric circles.
Thus, we have:
πR2 = 1386
`=> 22/7xx"R"^2 = 1386`
`rArr "R" = (1386xx7/22) "cm"^2`
⇒ R2 = 441 cm2
⇒ R = 21 cm
Also,
πr2 = 962.2
`=> 22/7xx"r"^2 = 962.2`
`⇒ r2 = (962.2 × 7/22) "cm"^2`
`=> "r"^2 = (962.2/10xx7/22)"cm"^2`
`=>"r"^2 =1225/4 "cm"^2`
`=> "r" = 35/2 "cm"`
∴ Width of the ring = (R - r)
`= (21 - 35/2) "cm"`
`= 7/2 "cm"`
= 3.5 cm
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