Question

The area of a triangle with vertices A(3, 0), B(7, 0) and C(8, 4) is ______.

Options

• 14

• 28

• 8

• 6

Answer 1

The area of a triangle with vertices A(3, 0), B(7, 0) and C(8, 4) is 8.

Explanation:

Vertices of the triangle are,

A(x₁, y₁) = (3, 0)

B(x₂, y₂) = (7, 0)

C(x₃, y₃) = (8, 4)

Area of triangle = `|1/2[x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)]|`

= `|1/2[3(0 - 4) + 7(4 - 0) + 8(0 - 0)]|`

= `|1/2[-12 + 28 + 0]|`

= `|1/2[16]|`

= 8

Therefore, the area of ΔABC is 8.