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The area bounded by y = sinxx, X-axis and the ordinates x = 0, x = π / 4 is ______.

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Question

The area bounded by y = `sinx/x`, X-axis and the ordinates x = 0, x = π / 4 is ______.

Options

  • equal to π / 4

  • smaller π / 4

  • greater π / 4

  • smaller `int_0^(π//4) tanx/x dx`

MCQ
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Solution

The area bounded by y = `sinx/x`, X-axis and the ordinates x = 0, x = π / 4 is smaller π / 4.

Explanation:

We have, x > 0

∴ sin x < x

`\implies sinx/x < 1`

`\implies int_0^(π//4) sinx/x dx < int_0^(π//4) 1 dx = π/4`

or `int_0^(π//4) sinx/x dx < π/4`

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