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Question
The apparent depth of an object at the bottom of a tank filled with a liquid of refractive index 1.3 is 7.7 cm. What is the actual depth?
Numerical
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Solution
Given:
Apparent depth = 7.7 cm
Refractive index, n = 1.3
Formula:
n = `"Real depth"/"Apparent depth"`
Real depth = n × Apparent depth
= 1.3 × 7.7
= 10.01 cm
The actual (real) depth is approximately 10 cm.
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