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The angle between the tangents to the curve y = x2-5x+6 at the points (2, 0) and (3, 0) is ______

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Question

The angle between the tangents to the curve y = `x^2 - 5x + 6` at the points (2, 0) and (3, 0) is ______ 

Options

  • `pi/3`

  • `pi/2`

  • `pi/6`

  • `pi/4`

MCQ
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Solution

The angle between the tangents to the curve y = `x^2 - 5x + 6` at the points (2, 0) and (3, 0) is `underline(pi/2)`. 

Explanation:

y = `x^2 - 5x + 6`

∴ `dy/dx = 2x - 5`

∴ `(dy/dx)_{(2, 0)} = 2(2) - 5 = -1 = "m"_1` (say)

and `(dy/dx)_{(3, 0)} = 2(3) - 5 = 1 = "m"_2` (say)

Here, m1 m2 = -1

∴ The required angle is `pi/2`.

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Application of Derivative in Geometry
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