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The adjoining figure represents a solid consisting of a cylinder surmounted by a cone at one end and a hemisphere at the other. Find the volume of the solid. - Mathematics

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Question

The adjoining figure represents a solid consisting of a cylinder surmounted by a cone at one end and a hemisphere at the other. Find the volume of the solid.

Sum
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Solution

Diameter of the cylindrical part = 7 cm

Therefore, radius of the cylindrical part = 3.5 cm

Volume of hemisphere `= 2/3pir^3 = 2/3xx22/7xx3.5xx3.5xx3.5 = 89.83  "cm"^3`

Volume of the cylinder `= pir^2h =22/7 xx 3.5 xx 3.5 xx 6.5 = 250.25  "cm"^3`

Height of cone = 12.8 − 6.5 − 3.5 = 2.8 cm

Volume of the cone = `1/3pir^2h =1/3 xx 22/7 xx 3.5 xx 3.5 xx 2.8 = 35.93  "cm"^3`

Total volume = 89.83 + 250.25 + 35.93 = 376.01 cm3

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Chapter 19: Volume and Surface Area of Solids - Exercise 19A [Page 763]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 19 Volume and Surface Area of Solids
Exercise 19A | Q 27 | Page 763
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