Advertisements
Advertisements
Question
The adjacent sides of a rectangle are x2 – 4xy + 7y2 and x3 – 5xy2. Find its area.
Advertisements
Solution
Reqd. area = (x2 – 4xy + 7y2) (x3 – 5xy2)
= x2 (x3 – 5xy2) – 4xy (x3 – 5xy2) + 7y2 (x3 – 5xy2)
= x5 – 5x3y2 – 4x4y + 20x2y3 + 7x3y2 – 35xy4
= x5 + 2x3y2 – 4x4y + 20x2y3 – 35xy4
= (x5 – 4x4y + 2x3y2 + 20x2y3 – 35xy4) sq. unit.
APPEARS IN
RELATED QUESTIONS
Multiply: 2y − 4y3 + 6y5 by y2 + y − 3
Simplify : (7x – 8) (3x + 2)
Simplify : (4x – 5y) (5x – 4y)
Simplify : (3y + 4z) (3y – 4z) + (2y + 7z) (y + z)
The base and the altitude of a triangle are (3x – 4y) and (6x + 5y) respectively. Find its area.
Find the value of (3x3) × (-5xy2) × (2x2yz3) for x = 1, y = 2 and z = 3.
Evaluate: xy2(x – 5y) + 1 for x = 2 and y = 1.
Evaluate: 2x(3x – 5) – 5(x – 2) – 18 for x = 2.
Multiply: (ab – 1) (3 – 2ab)
Simplify : (5 – x) (6 – 5x) (2 -x).
