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Question
The absolute refractive indices of water and glycerine are 1.33 and 1.46 respectively. Find the critical angle for a ray travelling from glycerine into water.
Numerical
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Solution
Given:
Refractive index of glycerine (denser medium), μ1 = 1.46
Refractive index of water (rarer medium), μ2 = 1.33
To Find:
Critical angle (C)
Formula:
sin C = `μ_2/μ_1`
sin C = `1.33/1.46`
sin C = 0.9109589
C = sin−1 (0.911)
C ≈ 65.6°
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