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Question
The absolute maximum value of the function f(x) = 2x3 − 3x2 − 36x + 9 defined on [−3, 3] is ______.
Options
36
53
63
72
MCQ
Fill in the Blanks
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Solution
The absolute maximum value of the function f(x) = 2x3 − 3x2 − 36x + 9 defined on [−3, 3] is 53.
Explanation:
Given f(x) = 2x3 − 3x2 − 36x + 9
Now f'(x) = 6(x2 − x − 6)
at f'(x) = 0
x2 − x − 6
x = −2, 3
f(−2) = 2(−2)3 − 3(−2)2 − 36(−2) + 9 = 53 will be absolute maximum value
f(−3) = −54 − 27 + 108 + 9 = 36
f(3) = 54 − 27 − 108 + 9 = −72
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