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The 24th Term of an Ap is Twice Its 10th Term. Show that Its 72nd Term is 4 Times Its 15th Term. - Mathematics

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Question

The 24th term of an AP is twice its 10th term. Show that its 72nd term is 4 times its 15th term. 

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Solution

Let a be the first term and d be the common difference of the AP. Then,

`a_24 = 2a_10`          (Given)

⇒ a + 23d = 2(a +9d)                   [a= a + (n-1) d]

⇒  a+ 23d = 2a - 18d

⇒  2a - a = 23d -18d

⇒  a = 5d          ..............(1)

Now , 

`(a_72)/(a_15) = (a+ 71d)/(a+14d) `

⇒  ` (a_72)/(a_15) = (5d + 71d)/(5d+14d)`              [From(1)]

⇒  `(a_72)/(a_15) = (76d)/(19d)=4`

⇒  `a_72 = 4 xx a_15`

Hence, the 72nd term of the AP is 4 times its 15th term. 

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Chapter 11: Arithmetic Progression - Exercises 1

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 11 Arithmetic Progression
Exercises 1 | Q 38

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