Advertisements
Advertisements
Question
Ten cards numbered 1 to 10 are placed in a box, mixed up thoroughly and then one card is drawn randomly. If it is known that the number on the drawn card is more than 4. What is the probability that it is an even number?
Sum
Advertisements
Solution
Let S = {1, 2, 3, …, 10}
n(S) = 10
Let A be the event of drawing a number greater than 4.
Then A = {5, 6, 7, 8, 9, 10}
n(A) = 6
∴ P(A) = `("n"("A"))/("n"("S")) = 6/10`
Let B be the event of getting a even number.
Then B = {2, 4, 6, 8, 10}
Now A ∩ B = {6, 8, 10}
n(A ∩ B) = 3
∴ P(A ∩ B) = `3/10`
We have to find P`("B"/"A")`
P`("B"/"A") = ("P"("A" ∩ "B"))/("P"("A")) = (3/10)/(6/10) = 3/6 = 1/2`
shaalaa.com
Is there an error in this question or solution?
