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Question
`int tan^-1((2tanx)/(1 - tan^2x))`dx = ______
Options
x2 + c
x3 + c
`x^2/2 + c`
`x^3/3 + c`
MCQ
Fill in the Blanks
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Solution
`int tan^-1((2tanx)/(1 - tan^2x))`dx = x2 + c
Explanation:
`int tan^-1((2tanx)/(1 - tan^2x))`dx = `inttan^-1(tan2x)dx`
= `int2x dx = 2.x^2/2 + c = x^2 + c`
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Some Special Integrals
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