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Question
Taking the example of chlorine, show that all halogens (except fluorine) can exhibit +l, +3, +5 and +7 oxidation states.
Long Answer
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Solution
- Chlorine and other halogens (except fluorine) can show multiple oxidation states due to the presence of vacant d-orbitals in their valence shells.
- They can excite their ns and np electrons to these d-orbitals, allowing unpaired electrons to participate in bonding.
- This leads to positive oxidation states of +1, +3, +5, and +7, as seen in chlorine compounds like Cl2O (+1), ClO2 (+4, related), \[\ce{ClO^-_3}\] (+5), and \[\ce{ClO^-_4}\] (+7).
- Fluorine lacks vacant d-orbitals and is highly electronegative, so it only exhibits −1 oxidation state.
Hence, all halogens except fluorine can show +1, +3, +5, and +7 oxidation states due to their ability to expand the octet using d-orbitals.
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